Do se zyada padon wale anupaat
Short mein jawab
Do se zyada padon wala anupaat, jaise masaale ka 8 : 4 : 2 : 1, kai raashiyon ki ek saath tulna karta hai. Do aise anupaat samaanupaati hain jab har pad ek hi gunak se badle; aadha karne par 4 : 2 : 1 : 0.5 milta hai. Poore ko aise anupaat mein baantne ke liye ek hissa = poora ÷ padon ka jod.
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Do se zyada raashiyaan
Anupaat sirf do sankhyaon tak seemit nahi hain. Viswanath ke masaala powder mein dhaniya ke beej (8 chammach), laal mirch (4), toor dal (2 chammach) aur methi ke beej (1 chammach) hain, isliye chaar cheezon ka anupaat 8 : 4 : 2 : 1 hai. Anupaat mein utne pad ho sakte hain jitni raashiyaan hon, bas sab ek hi gunak se badlein taaki sambandh samaanupaati rahe.
Swaad wahi rakhna
Puneet ko wahi powder chahiye par unke paas sirf 2 laal mirch hain, Viswanath ki 4 ki aadhi. Baaki sab bhi aadha hona chahiye: 4 chammach dhaniya, ek chammach toor dal aur 0.5 chammach methi. Naya anupaat 4 : 2 : 1 : 0.5 purane ke samaanupaati hai, likha jaata hai 8 : 4 : 2 : 1 :: 4 : 2 : 1 : 0.5. Aam taur par a : b : c : d :: p : q : r : s jab a ÷ p = b ÷ q = c ÷ r = d ÷ s.
Rang aur concrete
Rang. Baingani rang ke ek shade ke liye laal : neela : safed = 2 : 3 : 5 chahiye. Yasmin ke paas 10 litre safed hai. Safed 5 hisse hai, isliye ek hissa 10 ÷ 5 = 2 litre; laal 2 × 2 = 4 litre aur neela 3 × 2 = 6 litre, kul 20 litre baingani.
Concrete. Mazboot khambhon, beams aur chhaton ke liye cement, ret aur gitti 1 : 1.5 : 3 mein milte hain, aur mazbooti ke liye steel ki chhadein lagti hain. 3 bori cement ho to har pad ko 3 se guna karo: 3 : 4.5 : 9, yaani 3 + 4.5 + 9 = 16.5 bori concrete mishran.
Poore ko anupaat mein baantna
12 ko 2 : 1 mein baantne ke liye pad jodo (2 + 1 = 3), poore ko jod se bhaag do (12 ÷ 3 = 4) aur har pad ko usse guna karo: 8 aur 4. Zyada padon ke saath bhi yahi tareeka hai.
1 : 1.5 : 3 mein 110 ikai concrete ke liye ek set (1 + 1.5 + 3) 5.5 ikai banaata hai, aur 110 ÷ 5.5 = 20 set: 20 ikai cement, 30 ret aur 60 gitti. Formula ke roop mein, x ko a : b : c : … mein baantne par hisse x × a ÷ (a + b + c + …), x × b ÷ (a + b + c + …), aur aise hi hain. Isliye 50 mL baingani rang ke liye 50 × 2 ÷ 10 = 10 mL laal, 15 mL neela aur 25 mL safed chahiye.
Triangle mein anupaat
Triangle ke teeno kon milkar 180° hote hain, isliye 1 : 3 : 5 anupaat ke kon 20° ke 9 hisse banaate hain: 20°, 60° aur 100°. Bhujaayein bhi anupaat mein ho sakti hain. 3 : 4 : 5 anupaat ki bhujaaon wale triangle, jaise 3, 4, 5 cm ya 6, 8, 10 cm, sab ek hi samkon aakaar ke hain par size alag hai, isliye sab sarvaangsam (congruent) nahi hain. 1 : 3 : 5 anupaat ki bhujaayein triangle bana hi nahi sakti, kyunki 1 + 3, 5 se kam hai.
Ye kahan milte hain
Recipe, dawaai ki khuraak, khaad ke mishran, school ka timetable aur budget, sab kai padon wale anupaat istemaal karte hain. Yahi vichaar pie chart bhi banaata hai, jahan 360° ko data ke anupaat mein baanta jaata hai. Dekho pie chart kaise banaayein, vyutkram samaanupaat, chapter ke notes aur NCERT solutions.
Practice karo
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Laal : neela : safed = 2 : 3 : 5. 10 litre safed ke saath kitna laal chahiye?
Jawab dekho
Jawab: (b) 4 litre
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₹10, ₹5, ₹2 aur ₹1 ke sikke 4 : 3 : 2 : 1 mein kul 100 hain. ₹5 ke kitne sikke hain?
Jawab dekho
Jawab: (c) 30
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Triangle ke kon 1 : 3 : 5 anupaat mein hain. Sabse bada kon hai:
Jawab dekho
Jawab: (c) 100°
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150 minute ka session warm-up : batting : bowling : fielding = 3 : 4 : 3 : 5 mein bata hai. Har ek ka samay nikaalo.
Jawab dekho
Jawab: 3 + 4 + 3 + 5 = 15 hisse, isliye ek hissa 150 ÷ 15 = 10 minute: warm-up aur cool-down 30, batting 40, bowling 30 aur fielding 50 minute.
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Odiya : Hindi : English kitaabein = 3 : 2 : 1, aur Odiya kitaabein 288 hain. Hindi aur English kitaabon ki sankhya nikaalo.
Jawab dekho
Jawab: 3 hisse = 288 kitaabein, isliye ek hissa 96. Hindi = 2 × 96 = 192, English = 96.
Students ke sawal
Do se zyada padon wala anupaat kya hota hai?
Ye teen ya zyada raashiyon ki tulna karne wala anupaat hai, jaise cement : ret : gitti = 1 : 1.5 : 3. Iska matlab hai ki cement ki har ikai ke saath 1.5 ikai ret aur 3 ikai gitti jaati hai, aur mishran wahi rakhne ke liye teeno ko ek hi gunak se badalna padta hai.
Kisi raashi ko teen padon wale anupaat mein kaise baantein?
Pad jodo, raashi ko us jod se bhaag dekar ek hissa nikaalo, aur har pad ko usse guna karo. 50 mL rang ko 2 : 3 : 5 mein baantne par jod 10 hai, ek hissa 5 mL, aur maatraayein 10 mL, 15 mL aur 25 mL hain.
Kya koi bhi teen sankhyaayein triangle ki bhujaayein ho sakti hain?
Nahi. Kinhi do bhujaaon ka jod teesri se zyada hona chahiye. 3 : 4 : 5 anupaat wali bhujaaon se triangle banta hai, par 1 : 3 : 5 se nahi, kyunki 1 + 3 = 4, jo 5 se kam hai.
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