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Distributive property: jod ka guna

Short mein jawab

Distributive property kehti hai ki jod ya antar ka guna, guna-phalon ke jod ya antar ke barabar hota hai: 2 × (43 + 24) = 2 × 43 + 2 × 24. Isse samajh aata hai ki brackets kyun zaroori hain, aur guna jaldi hota hai, jaise 97 × 25 = 100 × 25 − 3 × 25 = 2425.

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Do logon ka bill

Lhamo aur Norbu hotel gaye, aur dono ne ek-ek vegetable cutlet ₹43 ka aur ek-ek rasgulla ₹24 ka order kiya. Har ek ka hissa 43 + 24 hai. Kya kul bill 2 × 43 + 24 ho sakta hai? Terms mein dekho to ye 2 × 43 aur 24 ka jod hai, yaani do cutlet aur sirf ek rasgulla ka paisa. Hamein poore hisse ka dugna chahiye, aur brackets theek yahi kehte hain: 2 × (43 + 24) = 2 × 67 = 134 rupaye.

Do hisson ka bill do cutlet aur do rasgulle ke bill jaisa hi hai, isliye 2 × (43 + 24) = 2 × 43 + 2 × 24 = 86 + 48 = 134. Agar dost Sangmu bhi wahi order lekar aa jaaye, to bill 3 × (43 + 24) = 201 rupaye hoga.

₹43 ka cutlet aur ₹24 ka rasgulla, do plates: 2 × (43 + 24) = 2 × 43 + 2 × 24 = 134, jabki 2 × 43 + 24 = 110 mein sirf ek rasgulla ka paisa hai
Do plates, ek jaisa order

Scouts aur guides ki panktiyan

Republic Day parade mein boy scouts 5-5 ki 4 panktiyon mein aur girl guides 5-5 ki 3 panktiyon mein chal rahe hain. Har samooh alag gino to 4 × 5 + 3 × 5 = 20 + 15 = 35. Pehle panktiyan gino to 4 + 3 = 7 panktiyan, har ek mein 5, yaani (4 + 3) × 5 = 35. Isliye 4 × 5 + 3 × 5 = (4 + 3) × 5.

5-5 ki 4 panktiyon mein scouts aur 3 panktiyon mein guides: 4 × 5 + 3 × 5 = (4 + 3) × 5 = 35
Parade mein scouts aur guides

Yahan bhi brackets matlab badalte hain: 5 × 4 + 3 = 23 hai, par 5 × (4 + 3) = 35. Aur kyunki jagah badalne se na jod badalta hai na guna, 5 × (4 + 3) = 5 × (3 + 4) = (3 + 4) × 5.

Saamaanya niyam

10 × 98 + 3 × 98 ko aise socho: das baar 98, aur phir teen baar aur 98. Ye terah baar 98 hai, isliye 10 × 98 + 3 × 98 = (10 + 3) × 98. Antar ke saath bhi aisa hi hai: chaudah baar 10 mein se chhe baar 10 hata do to aath baar 10 bachta hai, isliye 14 × 10 − 6 × 10 = (14 − 6) × 10. Shabdon mein, jod (ya antar) ka guna, guna-phalon ka jod (ya antar) hai. Chapter ki summary ise distributive property kehti hai: kisi sankhya ka bracket se guna, us sankhya ka andar ke har term se guna karne jaisa hai.

Das baar 98 aur teen baar 98 milkar 13 × 98; chaudah baar 10 mein se chhe hataane pe 8 × 10
Jod ya antar ka guna

Extra: 5 × (4 + 3) ko 5 panktiyon aur 7 column waale binduon ke aayat ki tarah bhi soch sakte ho. 4th column ke baad ek rekha ise 5 × 4 aur 5 × 3 ke do hisson mein baant deti hai, isliye kul 20 + 15 = 35.

Jaldi guna

Ye property kisi jaane hue guna ko zaroorat waale guna mein badal deti hai. 53 × 18 = 954 diya hai, 63 × 18 nikaalo: 63 = 53 + 10, isliye 63 × 18 = 53 × 18 + 10 × 18 = 954 + 180 = 1134. Mushkil guna bhi aasaan ho jaate hain. 97 ko 100 − 3 likho: 97 × 25 = 100 × 25 − 3 × 25 = 2500 − 75 = 2425. Isi tarah 95 × 8 = 800 − 40 = 760, 104 × 15 = 1500 + 60 = 1560 aur 49 × 50 = 2500 − 50 = 2450. Ye aksar lambe guna se jaldi hota hai, khaas kar jab koi sankhya 10, 50, 100 ya 1000 ke kisi multiple ke paas ho, jaise 98 × 7 ya 103 × 9.

Jaldi guna: 97 × 25, 95 × 8, 104 × 15, 49 × 50 aur 63 × 18, ek sankhya todkar
Ek sankhya todo, phir guna karo

Tasveer ki sankhyaon ka jod

Ye property jod mein bhi madad karti hai. 3 by 3 grid mein paanch 4 aur chaar 8 hain: 5 × 4 + 4 × 8 = 52. Har 8 ko ek 4 ke saath jodi banao to 4 × (4 + 8) + 4 = 52 bhi aata hai. 4 by 4 grid mein aath 5 aur aath 6 hain, to jod 8 × 5 + 8 × 6 = 8 × (5 + 6) = 88, aur kyunki har pankti ka jod 22 hai, ye 4 × 22 bhi hai.

Do tasveerein: paanch 4 aur chaar 8 ka jod 52; aath 5 aur aath 6 ka jod 88, har ek do ya teen tareekon se
Do tareekon se jodo

Ye kyun zaroori hai

Mann mein guna, jaldi bill aur aage chalkar algebra, sab ke peeche distributive property hai. Ye expressions ki value kaise nikalein aur terms aur brackets ke vichaaron ke saath kaam karti hai. Kitaab ke har sawaal ka jawab Chapter 2 ke NCERT solutions mein hai; poore Chapter 2 ke notes bhi dekho.

Practice karo

  1. Kaunsa expression (9 + 2) × 4 ke barabar hai?

    1. (a) 9 × 4 + 2
    2. (b) 9 × 4 + 2 × 4
    3. (c) 9 + 2 × 4
    4. (d) 9 × 2 × 4
    Jawab dekho

    Jawab: (b) 9 × 4 + 2 × 4

  2. 104 × 15 kya hai? (100 + 4) × 15 ka use karo.

    1. (a) 1504
    2. (b) 1460
    3. (c) 1560
    4. (d) 1500
    Jawab dekho

    Jawab: (c) 1560

  3. 53 × 18 = 954 diya hai. 63 × 18 kya hai?

    1. (a) 964
    2. (b) 1134
    3. (c) 1044
    4. (d) 1954
    Jawab dekho

    Jawab: (b) 1134

  4. 49 × 50 jaldi waale tareeke se nikaalo.

    Jawab dekho

    Jawab: 49 × 50 = (50 − 1) × 50 = 50 × 50 − 1 × 50 = 2500 − 50 = 2450.

  5. Khaali jagah bharo: 5 × (12 − 3) = 5 × 12 − 5 × ___.

    Jawab dekho

    Jawab: 3. 5 brackets ki dono sankhyaon ko guna karta hai: 5 × 12 − 5 × 3 = 60 − 15 = 45, aur 5 × 9 bhi 45 hai.

Students ke sawal

Class 7 Maths mein distributive property kya hai?

Ye niyam ki jod ya antar ka guna karna, har hisse ka alag guna karke jodne ya ghataane jaisa hai: 4 × 5 + 3 × 5 = (4 + 3) × 5 = 35. Chapter ise Lhamo aur Norbu ke hotel bill aur scouts aur guides ki panktiyon se dikhata hai, aur summary mein ise distributive property naam deta hai.

5 × 4 + 3 aur 5 × (4 + 3) barabar kyun nahi hain?

5 × 4 + 3 mein sirf 4 ka 5 se guna hota hai, phir 3 judta hai: 20 + 3 = 23. 5 × (4 + 3) mein poore jod 7 ka 5 se guna hota hai: 35. Doosra expression 5 × 4 + 5 × 3 ke barabar hai, yaani usme 3 ki jagah 5 × 3 = 15 hai.

Distributive property se guna jaldi kaise hota hai?

Ek sankhya ko gol sankhya aur chhoti sankhya ke jod ya antar mein todo, har hisse ka guna karo aur milao. 97 × 25 = (100 − 3) × 25 = 2500 − 75 = 2425, aur 104 × 15 = (100 + 4) × 15 = 1500 + 60 = 1560. Ye tab sabse kaam aata hai jab sankhya 10, 50 ya 100 ke kisi multiple ke paas ho.

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